Answer:
Upper Control Limit for a c-chart = 9.1
Step-by-step explanation:
Given - construction company has just constructed 150 new apartments. An external inspector is hired to do the final checking before they are given way to prospective customers. Inspector at random selects 8 apartments and and counts how many defects are in each one them. He finds 7,3, 2, 1, 2, 5, 4, 4 defects.
To find - What will be Upper Control Limit for a C chart ?
Proof -
Upper Control Limit for a c-chart = c bar + 3(square root of c bar)
Now,
c bar = = 3.5
∴ we get
Upper Control Limit for a c-chart = 3.5 + 3(square root of 3.5)
= 3.5 + (1.87)
= 3.5 + 5.61
= 9.1
⇒Upper Control Limit for a c-chart = 9.1
This equation is in point-slope form, which is y - b = m(x - a), where m is the slope and (a, b) is a point on the line.
The given equation is y - 11 = 14(x - 2). Given that m is the slope, the slope of this graph is 14. The point on the line is (2, 11) (the negative signs are part of the point-slope equation, and not the coordinates).
Answer:
A. (2, 11)
Answer:
Solution given;
diameter[d]=12
we
have
circumference of circle=πd=12π
<u>1</u><u>2</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
-3.
It's the same as normal division unless they have different signs, then it's negative.