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Genrish500 [490]
3 years ago
11

Help me pleaseee I’m still have more works to dooooo

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0
Iam sorry i cant see the qusetion
katrin2010 [14]3 years ago
7 0
1. r=2
2. r=2.5
3. r=?
4. r=2
5. r=3
6. r=1.2
7. r=1.2
8. r=2.6?
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HELLO AGAIN HERE'S ANTOHER QUESTION
puteri [66]
I believe it’s B but i’m not too sure.
4 0
3 years ago
If y = 7 what is the value of x
Katyanochek1 [597]

Answer:If y = 7 what is the value of x would be 7

Step-by-step explanation:

8 0
2 years ago
Suppose a water tank in the shape of a right circular cylinder is thirty feet high and eight feet in diameter. a) How much sheet
Zanzabum

Answer:

755.98 ft^2

Step-by-step explanation:

Height of the Cylinder= 30 feet

Diameter = 8 feet

Radius= Diameter/2 = 8/2 = 4 feet

The Amount of Metal Sheet used in constructing the tank is the Total  Surface Area of the Tank.

Total Surface Area of a Cylinder =

=2\pi r(r+h)\\=2*\pi*4(4+30)\\=8*\pi*30=\\=240\pi\\=755.98 ft^2

5 0
3 years ago
jack purchases 12 gallons of gas on monday .he uses 2/3 of amount purchased communting to and from work during the week addition
Zigmanuir [339]
Gallon he uses to and from work = (2 / 3) of 12

12 * (2 / 3)
= 8 ----- he uses 8 gallons to and from work

 + 2 additinal for errands

therefore gallons for work + gallons for errand = *8 + 2
= 10

your answer is 10
6 0
3 years ago
Please help me with the question
mars1129 [50]

(i) The mean is

\displaystyle E(X) = \sum_x x \, P(X = x) \\\\ E(X) = 1\cdot0.175 + 2\cdot0.315 + 3\cdot0.211 + 4\cdot0.092 + 5\cdot0.207 \\\\ \boxed{E(X) = 2.839}

The variance is

V(X) = E((X - E(X))^2) = E(X^2) - E(X)^2

Compute the second moment E(X^2) :

\displaystyle E(X^2) = \sum_x x^2 \, P(X = x) \\\\ E(X) = 1^2\cdot0.175 + 2^2\cdot0.315 + 3^2\times0.211 + 4^2\times0.092 + 5^2\times0.207 \\\\ E(X^2) = 9.997

Then the variance is

\boxed{V(X) \approx 1.9171}

(ii) For a random variable Z=aX+b, where a,b are constants, we have

E(Z) = E(aX+b) = E(aX) + E(b) = a E(X) + b

and

V(Z) = E((aX+b)^2) - E(aX+b)^2 \\\\ V(Z) = E(a^2 X^2 + 2ab X + b^2) - (a E(X) + b)^2 \\\\ V(Z) = a^2 (E(X^2) - E(X)^2) \\\\ V(Z) = a^2 V(X)

Then for Y=\frac{X+3}2, we have

E(Y) = \dfrac12 E(X) + \dfrac32 \\\\ \boxed{E(Y) = 2.918}

E(Y^2) = E\left(\left(\dfrac{X+3}2\right)^2\right) = \dfrac14 E(X^2) + \dfrac32 E(X) + \dfrac94 \\\\ \boxed{E(Y^2) \approx 9.0028}

3 0
2 years ago
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