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Nataly_w [17]
3 years ago
6

What is the solution to the system of equations? 2x+4y=12 Y=1/2x-3

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0
2x+4y=12 ------>1
y=1/2x-3. ------->2

2 into 1

2x+4(1/2x-3)=12
2x+2x-12=12
4x-12-12=0
4x-24=0
4x=24
x=24/4
x=6 ------> 3

3 into 2

y=1/2x-3
y=1/2(6)-3
y/=0


sorry if Im wrong or my is incorrect



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Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

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Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

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2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

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What is the slope of y = -4
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