<span>You first need to find the area of the living room.
Both of the two stores are dealing with square yard. The first thing you need to do is convert your feet to yards.
There are 3 feet in 1 yard. So divide the number of feet by 3 to get the yards.
12/3 = 4 yards
19/3 = 6.333 yards.
You then multiple those numbers to get your square yardage of the room (i.e. your area)
4*6.333 = 25.33333 sq. yards.
Now, look at what the first store is offering. You need to calculate the price. Originally, the carpet will cost $18 the number of square yardage for the carpet ONLY. So, multiple
$18 by your area of 25.33
18*25.333 = $456
Now, there is a sale of 20% off the carpet only price. You know the price so you need to take 20% of that and then subtract that number from the original total. Think of it like this. If you went and something was 50% off, and it was originally $10. 1/2 of 10 is 5. 10-5 is 5. That's the price you would pay. Use the same process with this problem.
$456*.20 = 91.20
(remember a % is the same as moving the decimal over 2 places.)
Take 91.20 off of 456
456-91.20 = 364.80
Then, find the installation price. They say that they will charge $2 per square yard. Your square yardage is 25.333. Now multiple those two numbers.
2*25.333=50.66
Add that price to the 364.80 to get the TOTAL for the first store.
364.80+50.66=415.47 (rounded off from 415.466)
Cindy's carpet:
they have $18 per square yard. Again, multiple 18 by your square yardage.
18*25.333 = 455.99
If it is 10% off, you go through the same process as before.
455.99*.10=45.59
Subtract that from the whole
455.99-45.59 = 410.40 </span>
Where’s the root to the question
K=8k+28
subtract 8k from both side
-7k = 28
divide both side by -7
k= -4
Answer:
x=0.y=3
Step-by-step explanation:
5x-y=-3
y=5x+3
sub y=5x+3 into 6x+y=3,
6x+5x+3=3
11x=0
x=0
6(0)+y=3
y=3
Answer:
The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;
Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.
