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SOVA2 [1]
3 years ago
11

A bag contains 3 red marbles and 8 blue marbles. A marble is drawn from the bag, the color recorded, then the marble is put back

into the bag. This process is repeated ten times, and we are interested in the number of blue marbles drawn. What would be the probability of success in this experiment
Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

0.0414

Step-by-step explanation:

Total number of marbles= 8+3= 11

8 blue and 3 red

Marbles are picked with replacement until 10 marbles are selected.

Probability of number of blue marbles choosen in 10 pick with replacement out of 11 marbles= ((8C1/11C1))^10

=(8/11)^10

=0.72723^10

= 0.0414

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Xy′ = √(1 − y2 ), y(1) = 0
Ulleksa [173]

Answer:

The particular solution is y=\sin (\ln|x|) .

Step-by-step explanation:

The given differential equation is

xy'=\sqrt {1-y^2}

It can be written as

x\frac{dy}{dx}=\sqrt {1-y^2}

Use variable separable method to solve the above equation.

\frac{dy}{\sqrt {1-y^2}}=\frac{1}{x}dx

Integrate both sides.

\int \frac{dy}{\sqrt {1-y^2}}=\int \frac{1}{x}dx

\sin^{-1} y=\ln|x|+C            .... (1)

It is given that y(1)=0. It means y=0 at x=1.

\sin (0)=\ln|1|+C

0=0+C

0=C

The value of constant is 0.

Substitute C=0 in equation (1) to find The required equation.

\sin^{-1} y=\ln|x|+0

Taking sin both sides.

y=\sin (\ln|x|)

Therefore the particular solution is y=\sin (\ln|x|) .

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