there are 226.796 grams in 8 ounces
Let Cedric's age be c
tyshon= 3c-3
3c-3 +c =3c+c-3 = 4c-3
4c-3=57
4c=60
c=15
tyshon=15×3-3 = 42
Answer: 2 1/3 feet
Step-by-step explanation:
3.5 / 1.5 = 2 1/3
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.
For more context let's look at the first equation in the problem that we can apply this to:

Through zero property we know that the factor

can be equal to zero as well as

. This is because, even if only one of them is zero, the product will immediately be zero.
The zero product property is best applied to
factorable quadratic equations in this case.
Another factorable equation would be

since we can factor out

and end up with

. Now we'll end up with two factors,

and

, which we can apply the zero product property to.
The rest of the options are not factorable thus the zero product property won't apply to them.
Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.