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Nimfa-mama [501]
2 years ago
12

What are the coefficients in the polynomial 4x2 + 3x-3?

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
4 0

                   - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

        What are the coefficients in the polynomial 4x²+3x-3?

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}\diamond

<u>Coefficient:-</u>  A number before a variable

<u>Coefficients in this polynomial:-</u>

4 (the number before x²) and 3 (the number before x)

<h3 />

So we conclude that the right option is:-

\bigcirc\!\!\!\!\!\large\checkmark 4, 3 (Option B)

<h3>Good luck.</h3>

            - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

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Answer:

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Step-by-step explanation:

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Notice, you are adding the previous two terms to get the third term per consecutive triples of the sequence.

That is:

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Yes, I'm naming the sequence f.

So I said a third term in a consecutive triple of the sequence is equal to the sum of it's two prior terms. Example, f(3)=f(2)+f(1) and f(4)=f(3)+f(2) and so on...

Note, the term before the nth term is the (n-1)th term and the term before the (n-1)th term is the (n-2)th term. Just like before the 15th term you have the (15-1)th term and before that one you have the (15-2)th term. That example simplified means before the 15th term you have the 14th and then the 13th.

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