Answer:
(t^2 -4) (t^2 +4)
(t-2)(t+2)(t^2+4)
Step-by-step explanation:
t^4 - 16
We can write this as the difference of squares
We know the dfference of squares is
(a^2 - b^2) = (a-b) (a+b)
( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4)
We can write t^2 -4 as the difference of squares
t^2 -4 = t^2 -2^2 = (t-2)(t+2)
Replacing this in
( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4) = (t-2)(t+2)(t^2+4)
Answer:
.35
Step-by-step explanation:
Answer:
Coefficients are 2, 5, -1. (Coefficients are the numbers before the x)
Constant is 3 (constant is the number without any x)
2x^5+0x^4+5x^3+0x^2-x+3
You start with the biggest and end with the smallest, if anything isnt present int he original equation (for example x^4 in this case) put it in with a zero before it.
Answer:
f = 2
g = 8
h = -9
k = 40
m = 1
Step-by-step explanation:
Equation 1:
23f - 17 = 29
Add 17 to both sides. This undoes the -17.
23f = 29 + 17
Add 17 to 29 to get 46.
23f = 46
Divide both sides by 23. This undoes the multiplication by 23.
f = 46/23
Divide 46 by 23 to get 2.
f = 2
Equation 2:
2(3g + 4) = 56
Divide both sides by 2. This undoes the multiplication by 2.
3g + 4 = 56/2
Divide 56 by 2 to get 28.
3g + 4 = 28
Subtract 4 from both sides. This undoes the +4.
3g = 28 - 4
Subtract 4 from 28 to get 24.
3g = 24
Divide both sides by 3. This undoes the multiplication by 3.
g = 24/3
Divide 24 by 3 to get 8.
g = 8
Equation 3:
h + 9 = 0
Subtract 9 from both sides. This undoes the +9.
h = 0 - 9
Any number subtracted from 0 gives its negation.
h = -9
Equation 4
3(k - 8) = 96
Divide both sides by 3. This undoes the multiplication by 3.
k - 8 = 96/3
Divide 96 by 3 to get 32.
k - 8 = 32
Add 8 to both sides. This undoes the -8.
k = 32 + 8
Add 8 to 32 to get 40.
k = 40
Equation 5:
5m - 5 = 0
Add 5 to both sides. This undoes the -5
5m = 0 + 5
Anything plus 0 gives itself.
5m = 5
Divide both sides by 5. This undoes the multiplication by 5
m = 5/5
Anything divided by itself gives you 1.
m = 1
Answer:
Step-by-step explanation:
