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3 years ago

Are equations (3x+9)=6 and x+3=2?

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

Answer:

They are the same

Step-by-step explanation:

They both equal -1

emmasim [6.3K]3 years ago

3 0

Answer:

dhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfk

Step-by-step explanation:

dfgsdfgjfsdpogjpdisfiodfsgjdfgoipgdsfjiojgidfjiogdfjgdosfjoigpdjoigfddhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfk

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Noone is helping with my questions and my mom said if I don't finish all my work I can't go to the amusement park :(

n200080 [17]

Answer:

how can i help you

Step-by-step explanation:

i will help

6 0

3 years ago

What is the difference between -2 and -6? 8 -8 -4 4

Sedaia [141]

Hi there! The word "difference" means to subtract. -2 - -6=4. Therefore, it would be the last one.

8 0

4 years ago

The area of a circular oil slick on the surface of the sea is increasing at a rate of [150m^2/s] how fast is the radius changing

Akimi4 [234]

Answer with Step-by-step explanation:

We are given that

$\frac{dA}{dt}=150m^2/s$

a.Radius =25 m

We have to find rate of change of radius.

We know that

Area of circle, $A=\pi r^2$

Differentiate w.r.t time

$\frac{dA}{dt}=2\pi r\frac{dr}{dt}$

Substitute the values then we get

$150=2\pi (25)\frac{dr}{dt}$

$\frac{dr}{dt}=\frac{150}{50\pi}=\frac{3}{\pi} m/s$

$\frac{dr}{dt}=\frac{3}{\pi} m/s$

b.A= $1000m^2$

Substitute the values then we get

$1000=\pi r^2$

$\pi=3.14$

$r^2=\frac{1000}{3.14}$

$r=\sqrt{\frac{1000}{3.14}}=17.8m$

$\frac{dA}{dr}=2\pi r\frac{dr}{dt}$

Substitute the values then we get

$150=2\pi(17.8)\frac{dr}{dt}$

$\frac{dr}{dt}=\frac{150}{2\pi(17.8)}=\frac{150}{35.6\pi}$ m/s

$\frac{dr}{dt}=\frac{75}{17.8\pi}$ m/s

4 0

3 years ago

-2 x 3/7 please help me!

Dimas [21]

Step-by-step explanation:

-2 x 3/7 = (-2 x 3) /7

= -6/7

7 0

3 years ago

Read 2 more answers

Show that p(x)=2x3−5x2−10x+5 has a real root.

FromTheMoon [43]

Let's pick an arbitrary value of 5.

$P(5) = 2(5)^{3} - 5(5)^{2} - 10(5) + 5$
$= 2(125) - 125 - 50 + 5$
$= 250 - 125 - 50 + 5$
$= 80 > 0$

Let's pick another arbitrary value: 1

$P(1) = 2 - 5 - 10 + 5$
$= -8 < 0$

Between these two values, the polynomial is continuous. This means for the two polynomial points to be satisfied, there must be at least one root between these two points.

We can either use the Intermediate Value Theorem or Newton's method to make a better approximation from there.

6 0

3 years ago