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Neporo4naja [7]
3 years ago
12

Security measures are sometimes described as a combination of physical, technical, and administrative (PTA) safeguards. Which of

these would be considered a technical safeguard? Legal-regulatory requirements. Locked doors and other physical barriers. Policies about who is granted access to what types of data. Measures including device data encryption, anti-malware software, and communications encryption.
Computers and Technology
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

Measures including device data encryption, anti-malware software, and communications encryption.

You might be interested in
Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
2 years ago
A computer hard disk starts from rest, then speeds up with an angular acceleration of 190 rad/s2 until it reaches its final angu
Nataly_w [17]
The first thing we are going to do is find the equation of motion:
 ωf = ωi + αt
 θ = ωi*t + 1/2αt^2
 Where:
 ωf = final angular velocity
 ωi = initial angular velocity
 α = Angular acceleration
 θ = Revolutions.
 t = time.
 We have then:
 ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
 ωi = 0
 α = 190 rad / s2
 Clearing t:
 753.60 = 0 + 190*t
 t = 753.60 / 190
 t = 3.97 s
 Then, replacing the time:
 θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
 θ1 = 1494.51 rad
 For (10-3.97) s:
 θ2 = ωf * t
 θ2 = (753.60 rad / s) * (10-3.97) s
 θ2 = 4544,208 rad
 Number of final revolutions:
 θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
 θ1 + θ2 = 961.57 rev
 Answer:
 the disk has made 961.57 rev 10.0 s after it starts up
3 0
2 years ago
Read 2 more answers
How do you take a picture on this app
damaskus [11]
The paper clip.

Hope this helped.

Can i have brainliest?
8 0
3 years ago
Levi wants to run 5 commands sequentially, but does not want to create a shell script. He knows that each command is going to ta
sergeinik [125]

Answer:

um

Explanation:

what subject is this again?

3 0
2 years ago
You want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you shoul
nikklg [1K]

If you want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you should type chmod a <u>t  <subdir>.</u>

<h3>What is Subdir?</h3>

The Definition of the term subdirectory is known to be a kind of an organizational directory that can be seen on a computer.

It is known to be one that can be found inside another directory  such as a subfolder. It is seen as the file a person is looking for and it is one that needs to have an extension.

Therefore, if you want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you should type chmod a <u>t  <subdir>.</u>

Learn more about directory from

brainly.com/question/14845522

#SPJ1

See full question below

You want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. To do so, you should type:

chmod a+_____ <subdir>

- s

- p

- b

- t

6 0
1 year ago
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