Question

The width of a rectangle is 9 in. shorter than its length.

Answer 1

The width of the rectangle is 12in and the length is 21in

Answer 2

Let the width be called x inches, so the length is x+9 inches (width is 9in shorter than length) and x>0

So the area = w*l = x(x+9)

=> x^2+9x=252
=> x^2+9x-252=0
=> x^2 - 12x + 21x - 252 = 0
=>x(x-12) + 21(x-12) = 0
=> (x-12)(x+21)=0
=> x = 12 or -21
but x>0

=> x = 12 in
=> width = 12 in
=> length = 12+9 = 21 inches

brainliest pls