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garri49 [273]
3 years ago
13

The width of a rectangle is 9 in. shorter than its length.

Mathematics
2 answers:
poizon [28]3 years ago
8 0
The width of the rectangle is 12in and the length is 21in
Gnoma [55]3 years ago
3 0
Let the width be called x inches, so the length is x+9 inches (width is 9in shorter than length) and x>0

So the area = w*l = x(x+9)

=> x^2+9x=252
=> x^2+9x-252=0
=> x^2 - 12x + 21x - 252 = 0
=>x(x-12) + 21(x-12) = 0
=> (x-12)(x+21)=0
=> x = 12 or -21
but x>0

=> x = 12 in
=> width = 12 in
=> length = 12+9 = 21 inches

brainliest pls
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The cost in dollars of making x items is given by the function C(x)=10x+900 .
Stella [2.4K]

For the given cost equation we have:

a) Fixed cost is $900.

b) For making 25 items the cost is $1150.

c) D: x ∈ [0, 150]

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<h3>Working with the cost equation.</h3>

Here we know that the cost equation is:

c(x) = 10*x + 900.

First, we want to get the fixed cost, it is given by evaluating the function in x = 0.

c(0) = 10*0 + 900 = 900

The fixed cost is 900.

b) Now we want to get the cost for making 25 items, to get this, we just evaluate in x = 25.

c(25) = 10*25 + 900 = 250 + 900 = 1150

c) Now, if the maximum cost is 2400, then the maximum number of items that we can make is x₀, such that:

c( x₀) = 2400 = 10*x₀ + 900

Solving for x₀ we get:

x₀ = (2400 - 900)/10 = 150

Now we want to get the range and domain.

We know that we can make between 0 and 150 items, so the domain is:

D: x ∈ [0, 150]

For the range, we know that the fixed cost for 0 items is 900, and the maximum cost is 2400, then the range is:

R: c ∈ [900, 2400]

If you want to learn more about domain and range:

brainly.com/question/10197594

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2 years ago
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Answer:

0 is the answer. I think.

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