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Quiz: Completing the Square 7 Solving Quadratic Equations

galina1969 [7]

Answer:

Step-by-step explanation:

x²-5x=12

x²-5x+(\frac{-5}{2})²=12+(frac{-5}{2})²

$(x-\frac{5}{2} )^2=12+\frac{25}{4} =\frac{73}{4} \\x=\frac{5}{2} \pm\frac{\sqrt{73} }{2}=2.5 \pm 4.272\\x\approx 6.772,-1.772\\\\x \approx 06.77,-1.77$

7 0

2 years ago

Select the correct answer. A farmers' group conducted an experiment to determine which fertilizer is better for plant growth. On

zloy xaker [14]

Answer:

Step-by-step explanation:

at the bottom it has a key and the key shows blue that had the urea supplement and green with out. the graph has a higher amount of growth for the plants with the urea supplement and green with about half the growth.

so you could say something like this: over the course of three months the plants with the urea supplement had almost double the amount of growth the plants without the urea supplement did, over all the the urea increased the amount of growth the plants had over the 3 month time span. :)

4 0

2 years ago

Read 2 more answers

What’s common difference 35,32,29,26

Vlad1618 [11]

3 is the common difference

7 0

2 years ago

Hi I'm a girl and if anyone need help come to me cause I'm here and I know every thing and I'm nice:)

alexira [117]

Uhmm ok thank uuuuuu

3 0

3 years ago

Read 2 more answers

Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f

AlladinOne [14]

Answer:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

$\hat p=0.64$ estimated proportion of interest

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:

Null hypothesis: $p =0.5$

Alternative hypothesis: $p > 0.5$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

7 0

3 years ago