Via synthetic division, we have
-3 | 1 8 19 12
... | -3 -15 -12
= = = = = = = = = = = =
... | 1 5 4 0
which is to say,
is the area of the base.
Answer:
Triangle OMN and Triangle OJK are similar by SAS Theorem
Step-by-step explanation:
we know that
The<u> Side-Angle-Side (SAS) Similarity Theorem</u> states that- If an angle of one triangle is congruent to an angle of a second triangle and the lengths of the sides including these angles are proportional, then the triangles must be similar.
In this problem we have
∠JOK≅∠MON
The corresponding sides including the congruent angle are
OK and ON
OJ and OM
Verify if the corresponding sides are proportional
substitute the given values
-----> is true
therefore
Triangle OMN and Triangle OJK are similar by SAS Theorem
Answer:
y=5×+2
Step-by-step explanation:
5(1)+2=7
5(2)+2=12
5(3)+2=17
5(4)+2=22
Answer:
A. StartRoot 3 EndRoot.
Step-by-step explanation:
We have to simplify the following expression
Now, we know that 27 = 3 × 3 × 3, hence .
And 12 = 2 × 2 × 3, hence
So, the given expression becomes
= 2 × 3√3 + 2√3 - 3√3 - 2 × 2√3
= 6√3 + 2√3 - 3√3 - 4√3
= √3
Therefore, the solution is A. StartRoot 3 EndRoot. (Answer)
Answer:
gayerhathwthwtyjnhsrgthxfgbsghsghsdghsg
Step-by-step explanation: