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Shtirlitz [24]
3 years ago
6

Find the volume of the following shapes. Round to tenths and don’t forget the units. Show your work!

Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

Step-by-step explanation:

1). Figure (1) comprises two cuboids, one small cuboid placed on the big cuboid at the bottom.

Volume of the figure = Volume of the cuboid on the top + Volume of the cuboid at the bottom

Volume of the cuboid on the top = Length × Width × Height

                                                   = 4 × 6 × 5

                                                   = 120 mm³

Volume of the cuboid at the bottom = Length × Width × Height

                                                        = 9 × 6 × 4

                                                        = 216 mm³

Volume of the figure = 120 + 216

                                   = 336 mm³

2). Figure shown in the picture has two parts,

Cone placed on the top of a cylinder.

Volume of the given figure = Volume of cone + Volume of cylinder

                                          = \frac{1}{3}\pi r^{2}h+\pi r^{2}h'

                                          = \frac{1}{3}\pi (\frac{3}{2})^{2}(3)+\pi (\frac{3}{2})^{2}(8.1)

                                          = \frac{9}{4}\pi +18.225\pi

                                          = (2.25+18.225)\pi

                                          = 20.475\pi

                                          = 64.3 ft³

Therefore, volume of the given figure = 64.3 ft³.

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(1 point) A chain 64 meters long whose mass is 24 kilograms is hanging over the edge of a tall building and does not touch the g
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Answer:

W = 2747,1 [J]

Step-by-step explanation:

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W₁ = ∫₀ᵇ F(y) dy

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W₂ = 3.675 * 51 * 13      Kg m² /s²   [J]

W₂ =  2436,53 [J]

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W₁  = ∫¹³₀ mgy dy    ⇒     W₁  = ∫¹³₀ 3,675 ydy

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W₁  = 310,54 [J]

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Square root of 121 is 11.
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