Y = (-1/2)x + (3/2)
is a line that will pass through (5, 1), though I have no idea what you want it to be perpendicular to, as you have no provided any other equation.
Answer: rate of train A = 120 km/h
rate of train B = 101 km/h
Step-by-step explanation:
Let x = the speed of train A
Let y = the speed of train B
One train travels 19 km/h slower than the other. Let train B be the slower train. Therefore,
x = y + 19 - - - - - - - - - -1
Recall
Speed = distance/time
Distance = speed × time
If they meet in 3 hours, it means that train A has travelled a distance of
x × 3 = 3x km
And train B has travelled a distance of y × 3 = 3y km
Train A and Train B were 663 kilometers apart when they left their respective destinations. They left at the same time and travelled towards each other. This means that if they meet in 3hours time, they must have covered a total of 663 km. Therefore,
3x + 3y = 663 - - - - - - - - - 2
Substituting x = y + 19 into equation 2, it becomes
3(y + 19) + 3y = 663
3y + 57 + 3y = 663
6y + 57 = 663
6y = 663 - 57 = 606
y = 606/6 = 101 km/h
x = y + 19 = 101 + 19
x = 120 km/h
Answer:
92
Step-by-step explanation:
subtract the largest and smallest number
Assuming "top two" are ranked first and second:
The coach can choose one out of 25 for the first and 24 for the second.
So there are 25*24=600 ways to choose.
If "top two" simply means the two best, without distinction, then we divide 600 by two to get 300 ways because the choice of the order can be reversed (AB instead of BA).
Math symbols were invented for a reason. They help communicate your intent. Here, it looks like you may intend
... f(x) = a(2^x)
When x=0, this will have the value "a". When x=1, this will have the value a^2. The appropriate selection is
... f(0) = 3 when a = 3
