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muminat
3 years ago
14

Please help. I'm stuck.

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0
The root \sqrt{10} can be converted into the power 10^{ \frac{1}{2} }. Therefore we can rewrite the problem as (10^{ \frac{1}{2} } )^ {\frac{3}{4} x} and then follow the exponent rules about a power to a power, multiplying 1/2 and 3/4 together.

Thus the problem becomes 10^{\frac{3}{8}x}, which then can be turned into \sqrt[8]{10} ^{3x}, making the last option our answer.

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Kim is reading a book with 380 pages. She read 20 pages each day until she reached Part 2 of the book. Part 2 of the book is 160
d1i1m1o1n [39]
If you divide 380 by 20, you get 19. To check this, multiply 20 x 19 to see 380. Hope this helps :D
6 0
3 years ago
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If you eat 2/3 of a very large pizza and are left with 12 slices, how many slices would there be in 1/
AnnZ [28]

aound 15 or it depends how many slices there were in the first place

4 0
3 years ago
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Lossa
kupik [55]

Answer:

P= 28.28 m

diagonal (d) 10m

6 0
3 years ago
Find the area between the graph please
vagabundo [1.1K]

The area of the region shown in the coordinate plane is 2.7823 units square.

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

It is given that:

The graph of a function:

y = sinx

And a line segment passed through:

(0, 0) and (7π/6, -1/2)

First, find the equation of the line:

y = (-1/2)/(7π/6)[x]

y = (-3/7π)x

The area by definite integration:

\rm Area = \int\limits^{7\pi/6}_0 {[sinx - (-3/7\pi)x]} \, dx

\rm Area = \int\limits^{7\pi/6}_0 {[sinx +3x/7\pi ]} \, dx

After solving the above definite integral:

Area = 2.7823 units square

Thus, the area of the region shown in the coordinate plane is 2.7823 units square.

Learn more about integration here:

brainly.com/question/18125359

#SPJ1

4 0
2 years ago
Simplify completely sqrt of 20Y^8
brilliants [131]

Answer:

Final answer is 2y^4 \sqrt{5}.

Step-by-step explanation:

Given expression is \sqrt{20y^8}.

Now we need to smplify the given expression \sqrt{20y^8}.

So begin with factoring 20 into two parts so that one part is perfect square number.

\sqrt{20y^8}

=\sqrt{4 \times 5y^8}

=\sqrt{4 y^8} \times \sqrt{5}

=2y^4 \times \sqrt{5}

Hence final answer is 2y^4 \sqrt{5}.

3 0
3 years ago
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