Your answer to this problem is
x<5/4
<u>General method</u><u>:</u>
Given numbers are 1.3 bar and 1.4 bar
- 1.3 bar = 1.333...
- 1.4 bar = 1.444...
Two rational numbers between them
= 1.3222... and 1.43333...
<u>Mean Method</u><u>:</u>
Let X = 1.333... → → →eqn(i)
since the periodicity is 1 then multiply eqn(i) with 10
⇛10×X = 1.333...×10
⇛10X = 13.333... → → →eqn(ii)
Subtract eqn(ii)-eqn(i)
10X = 13.333...
X = 1.333...
(-)
____________
9X = 12.000...
____________
⇛9X = 12
⇛X = 12/9
⇛X = 4/3
and
Let X = 1.444... → → →eqn(i)
since the periodicity is 1 then multiply eqn(i) with 10
⇛10×X = 1.444...×10
⇛10X = 14.444...→ → →eqn(ii)
Subtract eqn(ii)-eqn(i)
10X = 14.444...
X = 1.444...
(-)
____________
9X = 13.000...
____________
⇛9X = 13
⇛X = 13/9
Now we have 12/9 and 13/9
The rational number between them by mean method (a+b)/2
⇛{(12/9)+(13/9)}/2
⇛(25/9)/2
⇛25/18
and Second rational number
⇛{(12/9)+(25/18)}/2
⇛{(24+25)/18}/2
⇛(49/18)/2
⇛49/36
<u>Answer</u><u>:</u> The two rational numbers between them are 25/18 and 49/36.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?
brainly.com/question/85169?referrer
For the subtracting fractions, I would just make them into improper fractions (examples: 6/4, 5/3). To do that, you multiply whole number by the numerator (number on top of fraction), then add the denominator (number at the bottom), and finally, leaving the denominator as is.
Then make them have the same denominator. you might have to multiply or divide in order to match the denominators. then you may add or subtract straight across. NEVER change the denominator.
note: you might be required to make the improper fractions into mixed (ex: 4 1/2)
With multiplying, just multiply across (numerator × numerator, and denominator × denominator)
Answer:
36 tiles
Step-by-step explanation:
There will be 6 tiles in each direction, so the tiles covering the floor form a 6×6 array. The number needed is 6×6 = 36.
Answer:

Step-by-step explanation:
Kindly refer to the image attached in the answer region for labeling of triangle.
<em>AB </em><em>= 16
</em>
<em>BC </em><em>= 19</em>
<em>AC </em><em>= 15
</em>

We have to find the <em>angles </em><em>x</em> and <em>y</em> i.e.
.
Formula for <em>cosine rule</em>:

Where
<em>a</em> is the side opposite to
,
<em>b</em> is the side opposite to
and
<em>c</em> is the side opposite to
.

Similarly, for finding the value of <em>y:</em>

Hence, the values are:
