In order to divide $306 into the ratio of 9 to 5 to 3, first you have to make each section of the ratio represented by a variable, and put it into an equation.
9x + 5x + 3x = 306
Our next step is to simplify the left side of the equation by combining all of the like terms, the ones that contain variables.
17x = 306
Finally, to solve this equation, you have to divide both sides by 17 to isolate the variable x on the left side of the equation.
x = 18
However, this is not our answer as it isn't in a ratio format and doesn't really make sense. To find our ratio, we have to multiply each of our initial numbers (9, 5, and 3) by our variable, x.
9 * 18 = 162
5 * 18 = 90
3 * 18 = 54
You can verify that these numbers are correct because if you add them together you get 306.
Your final ratio is 162:90:54.
Hope this helps! :)
If you have a separate specific question about pre-tax prices and PMed me the link, I'd be happy to help you.
Answer: 300
Step-by-step explanation: First of all calcute how much per day, which is 5 miles. Then by 5 days which is 25. Now by 12 which is 300.
Hope this helped :)
Answer:
y=-10x+25
Step-by-step explanation:
Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of
.
- The standard deviation is of
.
- Sample of 100, hence

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:
Z = -2:

By the Central Limit Theorem




Z = 2:




The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213