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4 years ago

7

Can you help me with attached 3,5,7,and 9. .......30 points. Plz answer ASAP. Show work

1 answer:

lorasvet [3.4K]4 years ago

8 0

3) a^2+b^2=c^2
10^2+b^2=26^2
100+b^2=676
100-100+b^2=676-100
b^2=576
√b^2=√576
b=24
The rest are in the picture.
Pardon me please. My writing may look sloppy because I'm on bus

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Sam and Annika ride their bikes to school. Sam rides his bike (K )kilometers. Annika rides her bike two less than four times as

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4 years ago

A parallelogram has a base of 7 meters and a height of 10 meters. What is the area of the parallelogram in square meters?

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Step-by-step explanation:

Area of a parallelogram = H * B

Where ;H = height and B = 7

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<h3>placing in formula</h3>

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3 years ago

What is the prime factorization of 140?

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3 years ago

Read 2 more answers

A certain company reported selling 5,000 toys during the month of January and expects sales to grow at a rate of 7.5% per month

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Answer:

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3 years ago

Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo

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Given:

Equation of line $7x-4y=-12$ .

To find:

The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

$7x-4y+12=0$

Slope of line is

$\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

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$m_1=\dfrac{7}{4}$

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

$m_1m_2=-1$

$m_2=-\dfrac{1}{m_1}$

$m_2=-\dfrac{4}{7}$ $[\because m_1=\dfrac{7}{4}]$

Now, the slope of perpendicular line is $m_2=\dfrac{4}{7}$ and it goes through (-21,2). So, the equation of line is

$y-y_1=m_2(x-x_1)$

$y-2=-\dfrac{4}{7}(x-(-21))$

$y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)$

$y-2=-\dfrac{4}{7}x-12$

$y=-\dfrac{4}{7}x-12+2$

$y=-\dfrac{4}{7}x-10$

Therefore, the required equation in slope intercept form is $y=-\dfrac{4}{7}x-10$ .

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4 years ago