Answer:
Jeanette is the friend walking at the same rate as Caroline. This is because Jeanette also takes 1/5 of an hour to walk a mile.
Step-by-step explanation:
Note: This question is not complete. The complete question is therefore provided before answering the question as follows:
It takes Caroline 1/5 of an hour to walk a mile. Four of Caroline's friends time themselves on their own walk of different lengths. Which friend is walking at the same rate as Caroline? If:
David walked 1/2 a mile in 2/5 an hour
Jeanette walked 1/2 a mile in a 1/10 an hour
Kay walked 1/5 a mile 1/2 a hour
Mark walked 1/3 a mile in 3/5 an hour
The explanation of the answer is now given as follows:
To determine which friend is walking at the same rate as Caroline, we first convert their rate to number hours it takes to walk a mile as follows:
a. David walked 1/2 a mile in 2/5 an hour
This implies that:
(1 / 2) * 2 = 2/2 = 1 mile
(2 / 5) * 2 = 4/5 of an hour
Therefore, David takes 4/5 of an hour to walk a mile.
b. Jeanette walked 1/2 a mile in a 1/10 an hour
This implies that:
(1 / 2) * 2 = 2/2 = 1 mile
(1 / 10) * 2 = 2 / 10 = 1/5 of an hour
Therefore, Jeanette takes 1/5 of an hour to walk a mile.
c. Kay walked 1/5 a mile 1/2 a hour
This implies that:
(1 / 5) * 5 = 5/5 = 1 mile
(1 / 2) * 5 = 5 / 2 = 2.5 hours
Therefore, Kay takes 2.5 hours to walk a mile.
d. Mark walked 1/3 a mile in 3/5 an hour
This implies that:
(1 / 3) * 3 = 3/3 = 1 mile
(3 / 5) * 3 = (3 * 3) / 5 = 9 / 5 = 1.8 hours
Therefore, Kay takes 1.8 hours to walk a mile.
Conclusion.
Based on the calculations above, only Jeanette is walking at the same rate as Caroline. This is because Jeanette also takes 1/5 of an hour to walk a mile.
