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Dahasolnce [82]
1 year ago
5

A store charges a restocking fee for any returned item based upon the item price. An item priced at $200 has a fee of $12. An it

em priced at $150 has a fee of $9. Use ratios to prove the restocking fee is based on a proportional relationship. Explain your answer.
Mathematics
1 answer:
lyudmila [28]1 year ago
7 0

Answer:

Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.

Step-by-step explanation:

For the $200, the restocking fee is $12, so the ratio of the restocking fee to the price of the item is 12/200.

For the $150, the restocking fee is $9, so the ratio of the restocking fee to the price of the item is 9/150.

Now we find out if the ratios 12/200 and 9/150 are equal.

12/200 = 3/50

9/150 = 3/50

Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.

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Anyone help? don’t understand this question?
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Answer:

Step-by-step explanation:

Let the fraction is "x"

hence putt in box we get,

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2 years ago
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When a number is decreased by 4%, the result is 93. What is the original number
romanna [79]

Answer:

<u>The original number is 96.875</u>

Step-by-step explanation:

Let's find the original number using the Direct Rule of Three, this way:

       Percentage          Number

              100                       x

               96                       93

***********************************************

96x = 93 * 100

96x = 9,300

x = 9,300/96

x = 96.875

<u>The original number is 96.875</u>

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3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
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\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
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\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
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3 years ago
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