<span>y=2\3x-17and 4x-6y=-7 implies - 6y= - 4x -7, and then y= (-4/-6)x +7/6 and so
y=2/3x+7/6
but when we have y=ax+b and y=a'x+b', the two lines are parallels if a=a', in our case 2/3=2/3 the lines are parallel
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Answer:
The answer is y=-1/4x+11/16
Step-by-step explanation:
y-y=m(x-x1)
y-1=-1/4(x-(-5/4))
y-1=-1/4x-5/16
+1 +1
y=-1/4x+11/16