A linear equation of the form :
y = mx+b
can have at the most ONE x-intercept and at the most ONE y-intercept
I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis
Answer: domain: (-oo,oo) range: (0,oo)
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2. Please use
" ^ " to indicate exponentiation.
Rewrite 4x = 32 - x^2 in the standard form of a quadratic: x^2 + 4x - 32
Then the coefficients are a = 1, b = 4 and c = -32.
Find the discriminant. It is b^2-4ac.
Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.
Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.
So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."
Answer:
3
Step-by-step explanation:
