<img src="https://tex.z-dn.net/?f=%20log_%7Ba%7D%28%20%5Csqrt%7Ba%7D%20%5Csqrt%7Ba%7D%20%5Csqrt%7Ba%7D%29" id="TexFormula1" titl

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3 years ago

e=" log_{a}( \sqrt{a} \sqrt{a} \sqrt{a})" alt=" log_{a}( \sqrt{a} \sqrt{a} \sqrt{a})" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

ad-work [718]3 years ago

5 0

Step-by-step explanation:

$log_{a}(a) ^{x} = x$

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What is the value of the expression below if y=5

ale4655 [162]

Answer:

Step-by-step explanation:

Its a long step by step but trust me

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What is 4w=48 BTW I don't know the answer I tried really hard

AlexFokin [52]

4w = 48
Divide each side by 4. (division property of equality)
w = 12

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340 students went to the first school dance, the last school dance 306 students attended. What is the percent of change between

Fofino [41]

Answer:

10.59%

Step-by-step explanation:

percentage of change is given by

{(old number - new number)/old number} * 100

_________________________

given

no. of student went to the first school dance = 340

no. of student went to the last school dance = 306

Percentage of change between two dance

= ((no. of student went to the first school dance - no. of student went to the last school dance)/ no. of student went to the fist school dance)*100

= (340 - 306)/340 *100

= (36/340 )*100 = 10.59%

The percent of change between the two dances 10.59%.

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4 years ago

The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check

Verdich [7]

Answer:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma =150$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

$\bar X = \frac{740+920}{2} = 830$

and the margin of error is given by :

$ME = \frac{920-740}{2}= 90$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

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kap26 [50]

Answer:

B because it represents the lowest value

Step-by-step explanation:

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