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stellarik [79]
3 years ago
12

What fraction is equal to 3/5? 12/20 16/25 20/30 26/40

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0
12/20 is equivalent to 3/5. <span />
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Horatio drew a circle with a radius of 6x cm. Kelli drew a circle with a radius of 18y cm. What is the scale factor between thes
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I believe the answer Is A.x/3y.
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Find an equation of the line that passes through the points (5,- 4) and (2,-2).
Andru [333]

Answer:

y=-2/3x - 2/3

Step-by-step explanation:

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3 years ago
I literally dont understand this- help me with explanation please :')
spayn [35]

Answer:

The Triangles are not similar. (There are no s's in the triangle anywhere)

Step-by-step explanation: Look at the image and try to find the letters and trace the line its in.

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3 years ago
An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

4 0
3 years ago
X/3-4=-7<br><br> please help me solve
Vanyuwa [196]
In order to solve this we need to get x by itself on one side.

We need o start by adding across the 4 so that we get:

x/3 = -7 + 4 = -3

We then need to multiply both sides by 3 to get a singular x:

x = -3 * 3 = -9
5 0
3 years ago
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