Answer:
a=8b
Step-by-step explanation:
To do this we just need to isolate a
so we can multiply the equation by b
then we will get
a=8b
Answer:
34% decrease
Step-by-step explanation:
(V1-V2)/V1x100
450-297=153
153/450=0.34
0.34 x 100=34
34% decrease
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Answer:
a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:
![df = n-1= 10-1=9](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D%2010-1%3D9)
d.9
b) ![s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15](https://tex.z-dn.net/?f=s%5E2%20%3D%20%5Cfrac%7BSS%7D%7Bn-1%7D%3D%20%5Cfrac%7B600%7D%7B41-1%7D%3D%2015)
a.15
c) For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:
![SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80](https://tex.z-dn.net/?f=%20SE%20%3D%20%5Cfrac%7Bs%5E2%7D%7B%5Csqrt%7Bn%7D%7D%3D%20%5Cfrac%7B400%7D%7B%5Csqrt%7B25%7D%7D%3D%2080)
Step-by-step explanation:
Part a
For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:
![df = n-1= 10-1=9](https://tex.z-dn.net/?f=%20df%20%3D%20n-1%3D%2010-1%3D9)
d.9
Part b
From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:
![SS = \sum_{i=1}^n (X_i -\bar X)^2](https://tex.z-dn.net/?f=SS%20%3D%20%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2)
And the sample variance for this case can be calculated from this formula:
![s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15](https://tex.z-dn.net/?f=s%5E2%20%3D%20%5Cfrac%7BSS%7D%7Bn-1%7D%3D%20%5Cfrac%7B600%7D%7B41-1%7D%3D%2015)
a.15
Part c
For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:
![SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80](https://tex.z-dn.net/?f=%20SE%20%3D%20%5Cfrac%7Bs%5E2%7D%7B%5Csqrt%7Bn%7D%7D%3D%20%5Cfrac%7B400%7D%7B%5Csqrt%7B25%7D%7D%3D%2080)
<span>2x^3+3x^2-30x+7/x-3 divide</span>
Hi there!
You would use open intervals.
In the given inequality, the "<" sign is used, which means "greater than".
Open intervals would be used unless the inequality uses "≤" or "≥", which
mean "equal to or greater/less than". Closed brackets would be used in this
instance.