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dem82 [27]
3 years ago
5

On the average, actively managed mutual funds have an expense ratio of about __________ .

Mathematics
1 answer:
Butoxors [25]3 years ago
3 0
<span>A) 1.5 percent.
And here's a quizlet link to help you
</span><span>https://quizlet.com/81564997/finn-3003-ch-17-flash-cards/
</span>
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2 3 x - 4 = -2 plss tell meee
lions [1.4K]

Assuming you meant 2/3x -4= -2 the answer would be x=3

8 0
3 years ago
Please factorise the equations in the doc bellow ASAP. please show full working
ad-work [718]

Answer:

b. x² + 8x + 12 =

1. use the factoring X (see attachment)

2. 6 x 2 = 12; 6 + 2 = 12

3. (x + 6)(x + 2) = 0

4. x = -6, -2

c. x² + 13x + 12 =

1. 12 x 1 = 12; 12 + 1 = 13

2. (x + 12)(x + 1) = 0

3. x = -12, -1

c. x² + x - 12 =

1. 4 · (-3) = -12; 4 - 3 = 1

2. (x +4)(x - 3) = 0

3. x = -4, 3

f. x² + 15x + 36 =

1. 12 x 3 = 36; 12 + 3 = 15

2. (x + 12)(x + 3) = 0

3. x = -12, -3

hope this helps :)

8 0
3 years ago
Read 2 more answers
Please help me guys I will give the first person who answer a Brilliant
Stolb23 [73]

Answer:

2 3/4+(2 3/4 / 2)=t

Step-by-step explanation:

IM sure this is right

4 0
3 years ago
Which expression is equivalent to is m&lt;4?​
valkas [14]

m is less than or equal to 4

4 0
3 years ago
Read 2 more answers
1
liberstina [14]

By applying the midpoint rule, the midpoint of line segment FB is equal to point L.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

By critically observing the number line (see attachment), we can logically deduce the following parameters:

  • Point F is located at -2
  • Point B is located at 8.

By applying the midpoint rule, the midpoint of line segment FB is given by:

Midpoint of FB = (-2 + 8)/2

Midpoint of FB = 6/2

Midpoint of FB = 3.

In conclusion, a point which corresponds to 3 on the number line is point L.

Read more on midpoint here: brainly.com/question/8512667

#SPJ1

5 0
1 year ago
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