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Novay_Z [31]
3 years ago
9

If you wanted to predict the value of the y variable when the x variable is 15, you would be _____ the data.

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0
B) extrapolating ...

Serjik [45]3 years ago
4 0

Answer:

If you wanted to predict the value of the y variable when the x variable is 15, you would be extrapolating the data.

Step-by-step explanation:

If you wanted to predict the value of the y variable when the x variable is 15, you would be Extrapolating the data.

Extrapolation means, estimating the value of a variable beyond its given range.

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the base of the pyramid in the diagram is a regular hexagon. The length of each side of the hexagon is 6 ft and the height of th
miss Akunina [59]

Answer:

The volume of the pyramid is V=187\ ft^{3}

Step-by-step explanation:

we know that

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the base of the pyramid

H is the height of the pyramid

we have

B=93.5\ ft^{2}

H=6\ ft

substitute

V=\frac{1}{3}(93.5)(6)=187\ ft^{3}

5 0
3 years ago
Read 2 more answers
How many gallons of a 80​% antifreeze solution must be mixed with 100 gallons of 20​% antifreeze to get a mixture that is 70​% a
Blababa [14]

To Find :

How many gallons of a 80​% antifreeze solution must be mixed with 100 gallons of 20​% antifreeze to get a mixture that is 70​% antifreeze.

Solution :

Let, x gallons of 80​% antifreeze solution is required :

So,

(x \times 80) + ( 100 \times 20 ) = (x + 100 )\times 70\\\\8x + 200 = 7( x + 100)\\\\x = 500

Therefore, 500 gallons of 80% antifreeze solution is required.

6 0
3 years ago
3/5 ÷ 1 1/4 =<br> (20 points)
Anna11 [10]

3/5 ÷ 1 1/4 = 0.48

0.48 will be your anwer


7 0
3 years ago
What is the equivalent fraction Of 10 over 15
Rudiy27

Answer:

2/3

Step-by-step explanation:

4 0
3 years ago
Dada a Matriz A= [1 -2 1 ][-3 1 4] [0 6 8] , escreva uma matriz B diferente de A, tal que detA =detB.
Mariulka [41]

Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

\mathbf A=\begin{bmatrix}1&-2&1\\-3&1&4\\0&6&8\end{bmatrix}

\mathbf B=\mathbf A^\top=\begin{bmatrix}1&-3&0\\-2&1&6\\1&4&8\end{bmatrix}

3 0
3 years ago
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