What does -16i equal?

Mathematics

1 answer:

Alisiya [41]3 years ago

3 0

16i equals an amount to no other as it is majestic and formal. 16i equals nothing else than life it's self...

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Write a quadratic equation to represent a function with the vertex (-4, 1)

pishuonlain [190]

Answer:

y=a(x+4)^2 +1, for a real number a hat is different of 0.

Step-by-step explanation:

If we know only the vertex, there are many quandratic equations.

* Result: Vertex (m,n), the quadratic equation is y= a(x-m)^2 + n for a real number a that is different of 0.

Here, the vertex (-4,1), we have the equation: y=a(x+4)^2 +1, for a real number a hat is different of 0.

Hope you understand.

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Find the volume of each pyramid. Round to the nearest tenth if necessary.

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Step-by-step explanation:

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Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$