Total distance 5 km; at 5km / 0.65 h =
Second part distance: x; at 6 km/h, during t2
First part distance: 5 - x; at 8.75 km/h, during t1
V = d/t ⇒ t = d/V
t2 = x/6
t1=[5-x]/8.75
t2 + t1 = 0.65
x/6 + [5-x]/8.75 = 0.65
x/6 + 5/8.75 - x/8.75 = 13/20
x/6 - x/8.75 = 13/20 - 5/8.75
x/6 - 4x/35 =13/20 - 20/35
35x - 24x = (35*6)(35*13 - 20*20)/(20*35)
11 x = 16.5
x = 16.5/11 = 1.5 km
Answer:
B or 31r-71
Step-by-step explanation:
First, use distributive property to expand the first term.
30r-66-(5-r)
Remove the parenthesis of the third term:
30r-66-5+r
Combine like terms
31r-71
Answer:
width= 3.17
Step-by-step explanation:
Divide 38 (the area) by 12 (the width)
Answer:
-6.1
Step-by-step explanation:
Hope this helps!
