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3 years ago

Use the number line below, where RS = 7y + 2, ST = 2y +6, and RT = 13y - 12

Mathematics

1 answer:

Hitman42 [59]3 years ago

6 0

Answer: a. y=5

b. RS = 37 , ST =16 and RT = 53 .

Step-by-step explanation:

Given: On number line we have,

RS = 7y + 2, ST = 2y +6, and RT = 13y - 12.

a. Since its on number line so we have

RT = RS+ ST

i.e. 13y - 12 = (7y + 2) + ( 2y +6)

⇒ 13y - 12 = 7y + 2 + 2y +6

⇒ 13y-12 = 9y+8

⇒ 13y-9y = 8+ 12 [Subtract 9y from both sides and add 12 in both sides]

⇒ 4y = 20

⇒ y= 5 [Divide both sides by 4 ]

b. Now , RS = 7(5) + 2 = 35+2= 37,

ST = 2y +6 = 2 (5)+6 = 10+6 =16,

and RT = 13y - 12 = 13 (5)-12 = 65-12 = 53.

Hence, RS = 37 , ST =16 and RT = 53 .

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