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3 years ago

(3^6)^-2/(6^-9*-2^10)

1 answer:

6 0

$\frac{(3^{6})^{-2}}{(6^{-9}*-2^{10})}\\
\frac{3^{-12}}{(6^{-9}*-2^{10})}\\
\frac{6^{9}}{(3^{12}*-2^{10})}\\
\frac{10077696}{531441*-1024}=-0.0185185$

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The dimensions of a gymnastic floor are 40 ft by 40 ft. the performance floor is 1 ft less, or 39 ft, per side.

Mashutka [201]

Answer:

the square root of 3200

Step-by-step explanation:

I'm not sure if this is right, because the format of the question wasn't clear, but it sounded like we have to find the diagonal distance of the room from one corner to the opposite. If the sides are 40ft long on both sides, we can use the Pythagorean Theorem to solve this:

40^2+40^2=c^2

1600+1600=c^2

3200=c^2

c=sqrt(3200)

or about 56.5

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2 years ago

The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro

ra1l [238]

Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

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3 years ago

You purchased xyz common shares for $45 per share one year ago. one year later aftering receiving $4 dividend per share, you sol

Pepsi [2]

The return for the investment is C, or 15.56%. You add the dividend and the capital gain, $4+$3=$7, and then divide by the initial investment price, or $45. 7/45=.1556, or 15.56%.

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3 years ago

What is the mean of the values in the dot plot? Enter your answer in the box.

ziro4ka [17]

Answer:

The mean is 19.5

Step-by-step explanation:

You have to add all of the numbers up then divide by how many numbers there are.

Ex: 5, 5, 6, 7

add them up and you get 23

Divide 23 by how many numbers you have, which in this case, is 4

The answer to this example would be 5.75

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3 years ago

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -36 and 2304, respectively.

Lorico [155]

Answer:

I think it's B.)

Step-by-step explanation:

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3 years ago