Question

PLZ HELP!! Which real numbers are zeroes of the function?

Answer 1

The correct answers are: 1/2, 2 and -2.

To get this, factor f(x)

f(x)=2x^3-x^2-8x+4

f(x)= (2x^3-x^2) - (8x -4)

f(x)= (2x-1)(x^2) + (2x-1)(-4)

f(x)= (2x-1)(x^2-4)

f(x)= (2x-1)(x-2)(x+2)

2x-1=0

2x=1

x=1/2

x-2=0

x=2

x+2=0

x=-2