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abruzzese [7]
3 years ago
8

The formula for the area of a triangle is a=1/2bh. Hiro is solving the equation for h; his work is shown below. What mistake did

Hiro make?
a=1/2bh
2(x)a=2(x)(1/2bh)
2a=bh
2a-b=h
(x) is multiplication sign btw
Hiro should have divided both sides of the equation by 2. Hiro should have divided both sides of the equation by b. Hiro should have added b to both sides of the equation. Hiro should have subtracted 2 from both sides of the equation.
Mathematics
2 answers:
pav-90 [236]3 years ago
5 0
<h2>Hiro should have divided both sides of the equation by 2.</h2>

Example

If b = 5 and h = 10

<u>a = 1/2 * b * h</u>

a = 1/2 * 5 * 10

a = 25

<u>2a = 2 (1/2 * b * h)</u>

2 * 25 = 2 (1/2 * 5 * 10)

50 = 2 (25)

50 = 50

<u>2a = b * h</u>

2 * 25 = 5 * 10

50 = 50

2a - b = h

2 * 25 - 5 = 10

50 - 5 = 12

45 = 10

This is false.

If Hiro divided both sides by 2 instead:

2a ÷ 2 = b * h ÷ 2

2 * 25 ÷ 2 = 5 * 10 ÷ 2

50 ÷ 2 = 50 ÷ 2

25 = 25

xenn [34]3 years ago
5 0

Answer:

Hiro should divide both sides by 2.

Step-by-step explanation:

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