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Morgarella [4.7K]
4 years ago
12

Give an example of two whole number factors with a product of 9

Mathematics
1 answer:
notsponge [240]4 years ago
8 0
3 and 3 because 3x3=9
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Write the equation of the line in fully simplified slope-intercept form.
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Step-by-step explanation:

y — yı = m(x – xı) equation of a line

Points A(1,3) and B(2,1)

Slope (m) = (y2 – y1) / (x2 – x1)

(1 –3) / (2 – 1)

–2/1

–2

Thus, y –3 = –2 (x – 1)

y – 3 = –2x + 2

y –3 + 3 = –2x + 2 + 3

y = –2x + 5

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Find the difference (10m+3)-(4m-2)
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6m + 5

Step-by-step explanation:

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A piece of ribbon that is 8 and 1/3 yards long will be cut into 5 equal pieces to make bows. How much ribbon will be used foe ea
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The base of this pyramid is a rectangle. How many congruent faces does this pyramid have?
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A cube is a special prism which has bases and faces that are all squares. A pyramid is a polyhedron with only one base. The shape of the base determines the specific name of each pyramid. The faces are always triangles that meet at a common vertex.

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From a bowl containing five red, three white, and seven blue chips, select four at random and without replacement. Compute the c
snow_lady [41]

Answer:

The probability is \frac{5}{9}

Step-by-step explanation:

Let A be the event of one red, zero white, and three blue chips,

And, B is the event of at least three blue chips,

Since, A ∩ B = A (because If A happens that it is obvious that B will happen )

Thus, the  conditional probability of A if B is given,

P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}=\frac{P(A)}{P(B)}

Now, red chips = 5,

White chips = 3,

Blue chips = 7,

Total chips = 5 + 3 + 7 = 15

Since, the probability of one red, zero white, and three blue chips, when four chips are chosen,

P(A)=\frac{^5C_1\times ^3C_0\times ^7C_3}{^{15}C_4}

=\frac{5\times 35}{1365}

=\frac{175}{1365}

=\frac{5}{39}

While, the probability that of at least three blue chips,

P(B)=\frac{^8C_1\times ^7C_3+^8C_0\times ^7C_4}{^{15}C_4}

=\frac{8\times 35+35}{1365}

=\frac{315}{1365}

=\frac{3}{13}

Hence, the required conditional probability would be,

P(\frac{A}{B})=\frac{5/39}{3/13}

=\frac{65}{117}

=\frac{5}{9}

4 0
3 years ago
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