Answer:
334.4 m²
Step-by-step explanation:
The formula for the area of a sector is given as:
1/2 × r² × θ
Where θ = Central angle
Area of a Circle = 700 m²
The formula for the area of a circle = πr²
r = Radius of a circle
r² = Area / π
r = √Area / π
r = √700/π
r = 14.927053304 m
Approximately, r = 14.93 m
Therefore, the area of the sector
= 1/2 × r² × θ
= 1/2 × 14.93² × 3 rad
= 334.35735 m²
Approximately, Area of the sector = 334.4 m²
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:
Horizontal asymptote at y = 0.
<h3>What are the horizontal asymptotes of a function?</h3>
They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.
Researching this problem on the internet, the functions are given as follows:
.
The limits are given as follows:


Hence, the correct statement is:
Horizontal asymptote at y = 0.
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Answer:
y = 3.5x - 12.5
Step-by-step explanation:
First, find the slope using rise over run (y2 - y1 / x2 - x1) with the 2 points:
(-2 - 5) / (3 - 5)
-7/-2
= 3.5
Then, plug the slope and a point into y = mx + b to solve for b:
y = mx + b
5 = 3.5(5) + b
5 = 17.5 + b
-12.5 = b
Plug the slope and the y intercept into the equation y = mx + b
y = 3.5x - 12.5 will be the equation