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valentina_108 [34]
3 years ago
15

The 1997 value of an object was $9500. In 2012, it was worth $5000. The annual percent of decay has been constant. What is the a

nnual percent of decay? A) 1.19% B) 2.19% C) 3.19% D) 4.19%
Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer:

  • The answer is D.

Step-by-step explanation:

If the object starts with a value V_0, and a annual percent of decay <em>d, </em>after a year the value will be

V_1 = V_0 * d

after 2 years, taking now  V_1 as the starting value

V_2 = V_1 * d = V_0 * d * d

V_2 = V_0 * d^2

and so on, after <em>n years</em> the value will be:

V_n = V_0 * d^n

Now, in 1997 the value was $9500, in 2012 the value was $5000. Between 1997 and 2012 there are 15 years, so, our equation will be:

\$5000 = \$ 9500 * d^{15}

Working it a little

\frac{\$5000}{\$ 9500} = d^{15}

(\frac{\$5000}{\$ 9500})^{1/15} = d

(0.5263})^{1/15} = d

0.9581 = d

This mean that, after a year, the value will be at 95.81 %, this is, a decay rate of 4.19%.

vova2212 [387]3 years ago
5 0
Hello,

Here is your answer:

The proper answer to this question is option D "4.19%".

Your answer is D.

If you need anymore help feel free to ask me!

Hope this helps!
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Step-by-step explanation:

Let the amount of salt in a tank be =\frac{salt in the tank}{volume of salt in the tank}

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