Hey there!
To solve this problem, first turn the mixed numbers to improper fractions then multiply 2 2/3 and 1 1/4 . . .
2 2/3 = 8/3
1 1/4 = 5/4
8 x 5 = 40
3 x 4 = 12
= 40/12
Simplify 40/12 . . .
40/12 = 3 1/3 <--------
The answer to your question is option B.
The bananas weighed 3 1/3 pounds.
Hope this helps you.
Have a great day!
So first we need to find the total before tax. Let's add up the two prices:

So we know that the total before tax is $381. Now we are told that the sales tax on these items is 6.5%. It would be easier for us to convert 6.5% to a decimal in order to multiply. Let's convert 6.5% to a decimal by dividing by 100:

Now that we have the sales tax in decimal form, let's multiply this sales tax by the total amount of the items before tax ($381):

This means that $24.77 is the tax for this purchase. To find the total amount that Jon paid for these items after tax, you must add the tax to the total amount before tax to give you:

So now we know that
Jon's total bill for these items is $405.77.
Answer:
A
Step-by-step explanation:
SAS = side-angle-side
This means that, in order to prove that the triangles are congruent, they must have two congruent sides with the angle between them to the same.
We know that sides AB, ED, AC, and DF are all congruent as they all have a single mark through them. From this, you can conclude that the triangles already share two sides. All we need now is the angles in between to be congruent. This means that angle A and angle D need to be congruent.
I hope this helps!
When dealing with statistics (probabilities of events etc) and histograms