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erastova [34]
3 years ago
12

What is the following number in the sequence? What is the sequence's equation? 9, 15, 21, 27, __

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0
Its going up by 6, the answer is 33
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Multiply
Dmitriy789 [7]

Answer:

The product of given two fractions is

\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Step-by-step explanation:

Given expression is  

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}

To find the product of two given fractions as below :

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{2(5)}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{10}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{20x(x+2)}{5x(x-1)(x+3)}

=\frac{20x^2+40x}{(5x^2-5x)(x+3)} (multiply each term in the factor to each term in the another factor )

=\frac{20x^2+40x}{5x^3+15x^2-5x^2-15x}  ( adding the like terms )

=\frac{20x^2+40x}{5x^3+10x^2-15x}

=\frac{5x(4x+8)}{5x(x^2+2x-3)}

=\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Therefore the product of given two fractions is \frac{4(x+2)}{(x-1)(x+3)}

6 0
3 years ago
Given f(x) = 2x + 1, find the range value if the domain value is 1.75.
MAXImum [283]

Given:

The function is

f(x)=2x+1

To find:

The range value if the domain value is 1.75.

Solution:

Domain is the set of input values and range is the set of output values.

Here, range value if the domain value is 1.75. It means the value of function f(x) at x=1.75.

Substitute x=1.75 in the given function.

f(1.75)=2(1.75)+1

f(1.75)=3.5+1

f(1.75)=4.5

Therefore, the required range value is 4.5.

4 0
3 years ago
What is the f(n) runtime of the following pseudocode: sum = 0 for A = N/2 downto 1 for B = 1 to 4N increment sum by B
nikitadnepr [17]

Answer:

f(N) = 2+ N/2 + 6N² units of time.

Step-by-step explanation:

Assigning 0 to the variable sum takes one unit of time.

Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have

f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).

5 0
3 years ago
if the value of c is negative, you would need zero pairs to model the factorization of the polynomial. the x-tiles on the board
Yuliya22 [10]

Answer:

value of c is negative

constant are in factor bla bla.

Step-by-step explanation:

6 0
2 years ago
-3(_x + 4) = 9x – 12 Using the distributive property, what number would go in the blank in order for the given statement to be c
Licemer1 [7]

Answer:

-3(-3x + 4) = 9x - 12

Step-by-step explanation:

-3( Ax + 4) = 9x - 12

-3Ax -12 = 9x - 12

Equating coefficients of  x terms on both sides :

-3A = 9

A = -3

Therefore, -3(-3x + 4) = 9x - 12

4 0
3 years ago
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