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ExtremeBDS [4]
2 years ago
10

Determine whether the relation below is also a function.

Mathematics
1 answer:
Bess [88]2 years ago
3 0

Answer:

B. Not a function

Step-by-step explanation:

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Pls help asap thx alot<br><br>Find the missing vertical angles​
Vladimir79 [104]

Answer:

Vertical angles are congruent, so L3 = 37 degrees, and L4 = 143 degrees.

Let me know if this helps!

6 0
2 years ago
Find 48% of 30. Please help
baherus [9]

Answer:

14.4 would be the answer hope this is helpful

Step-by-step explanation:

14.4/30= 48%

4 0
2 years ago
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Fr.ee points and offering brainliest for the best reply<br> and what is 1 + 1?<br> 25 points
nikitadnepr [17]

Answer:

2, your most gracious highness, superior leader of the Northern hemisphere

Step-by-step explanation:

3 0
2 years ago
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Let X1, X2, ... , Xn be a random sample from N(μ, σ2), where the mean θ = μ is such that −[infinity] &lt; θ &lt; [infinity] and
Sliva [168]

Answer:

l'(\theta) = \frac{1}{\sigma^2} \sum_{i=1}^n (X_i -\theta)

And then the maximum occurs when l'(\theta) = 0, and that is only satisfied if and only if:

\hat \theta = \bar X

Step-by-step explanation:

For this case we have a random sample X_1 ,X_2,...,X_n where X_i \sim N(\mu=\theta, \sigma) where \sigma is fixed. And we want to show that the maximum likehood estimator for \theta = \bar X.

The first step is obtain the probability distribution function for the random variable X. For this case each X_i , i=1,...n have the following density function:

f(x_i | \theta,\sigma^2) = \frac{1}{\sqrt{2\pi}\sigma} exp^{-\frac{(x-\theta)^2}{2\sigma^2}} , -\infty \leq x \leq \infty

The likehood function is given by:

L(\theta) = \prod_{i=1}^n f(x_i)

Assuming independence between the random sample, and replacing the density function we have this:

L(\theta) = (\frac{1}{\sqrt{2\pi \sigma^2}})^n exp (-\frac{1}{2\sigma^2} \sum_{i=1}^n (X_i-\theta)^2)

Taking the natural log on btoh sides we got:

l(\theta) = -\frac{n}{2} ln(\sqrt{2\pi\sigma^2}) - \frac{1}{2\sigma^2} \sum_{i=1}^n (X_i -\theta)^2

Now if we take the derivate respect \theta we will see this:

l'(\theta) = \frac{1}{\sigma^2} \sum_{i=1}^n (X_i -\theta)

And then the maximum occurs when l'(\theta) = 0, and that is only satisfied if and only if:

\hat \theta = \bar X

6 0
3 years ago
Sandra uses 1/9 of a bottle of honey to make 1 pitcher of lemonade. How many pitchers of lemonade can she make with 3 bottles?
marusya05 [52]

Answer:

27 pitchers

Step-by-step explanation:

⅑ bottle of honey  =    1 pitcher       Multiply both sides by 9

1 bottle of honey  =    9 pitchers     Multiply both sides by 3

3 bottles of honey = 27 pitchers


4 0
3 years ago
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