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Inessa [10]
3 years ago
5

Lines pp and qq are parallel. The slope of line pp is −3-3. What is the slope of line qq?​

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0
-2 x 1 y = -1
Find the slope of this line
make y the subject
1 y = 2 x -1
Divide by 1
y = 2 x -1
Compare this equation with y=mx+b
slope m = 2
The slope of a line parallel to the above line will be the same
The slope of the required line will be 2
m= 2 ,point ( 2 , -2 )
Find b by plugging the values of m & the point in
y=mx+b
-2 = 4 + b
b= -6
m= 2
Plug value of the slope and b in y = mx +b
The required equation is y = 2 x -6
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Find the midpoint between (8,1) and (-1,3).
butalik [34]

Answer

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Step-by-step explanation

You add the x coordinates and divide it by 2, 8-1/2=3.5. Then you would do the same for the y coordinates 1+3/2=2. The midpoint would be (3.5,2)

3 0
3 years ago
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A rectangle has a length of 72 cm and a width of 56 cm. The other rectangle has the same area as this one, but its width is 21cm
andrew-mc [135]

Answer: I think it’s 4032

Step-by-step explanation:

8 0
4 years ago
A shop has a sale that offers 20% off all prices.On the final day reduce all the sale prices by 25%.Linz buys a radio on the fin
Mrac [35]

Answer:

40%

Step-by-step explanation:

Original price = x

Sale = 20% off

20% / 100 = 0.2 to convert from a percent to a decimal

Sale = x - 20% of x = x - 0.2x = 0.8x

Sale price = y = 0.8x

Reduction of sale prices = 25% = 0.25

Reduction = y - 25% of y = y - 0.25y = 0.75y

End price in terms of original price (x):

0.75y = 0.75(0.8)x

          = 0.6x

End price = 0.6 or 60% of original price, coming out to a 100-60 = 40% overall percentage reduction

5 0
3 years ago
Specifications call for the wall thickness of two-liter polycarbonate bottles to average 4.0 mils. A quality control engineer sa
bija089 [108]

Answer:

The null hypothesis μ=4.0 could not be rejected.

Step-by-step explanation:

In this problem we have to perform a hypothesis test of the mean, with s.d. of the population unknown.

The sample is: [3.999, 4.037, 4.116, 4.063, 3.969, 3.955, 4.091]

This sample has a mean of 4.033 and a standard deviation of 0.061.

The null and alternative hypothesis are:

H_0: \mu = 4.0\\\\H_1: \mu \neq 4.0

We assume a significance level of 0.05.

The test statistic for this test is:

t=\frac{M-\mu}{\sigma}=\frac{4.033-4.0}{0.061}=0.536

We have a sample size n=7, so the degrees of freedom are 7-1=6.

For a two-tailed test, t=0.536 and df=6, the P-value can be look up in a t-table.

The P-value is 0.61. Is greater than the significance level, so the effect is not significant and the null hypothesis can't be rejected.

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4 years ago
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