75,000 is the answer!
If this was the appropiate answer make sure to mark as the brainliest!
-procklown
D
Due to the question being the question
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Given
sin²x + 7cosx + 17
=1 - cos²x + 7cosx + 17
= - cos²x + 7cosx + 18 ← factor out - 1 from each term
= - (cos²x - 7cosx - 18)
Consider the factors of the constant term (- 18) which sum to give the coefficient of the cosx term (- 7)
The factors are - 9 and + 2, thus
= - (cosx - 9)(cosx + 2) ← in factored form
Answer:
The answer is "
"
Step-by-step explanation:
Given:
Find critical points:
differentiate the value with respect of x:
![\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r} \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]](https://tex.z-dn.net/?f=%5Cto%20g%27%28x%29%3D%20%28x-e%29%5E3%20%5Cfrac%7Bd%7D%7Bdx%7De%5E%7Be-r%7D%20%2Be%5E%7Be-r%7D%20%20%5Cfrac%7Bd%7D%7Bdx%7D%28x-e%29%5E3%3D%28x-e%29%5E2%20e%5E%7B%28e-x%29%7D%20%5B-x%2Be%2B3%5D)
critical points 
![\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3](https://tex.z-dn.net/?f=%5Cto%20%28x-e%29%5E2%20e%5E%7B%28e-x%29%7D%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20e%5E%7B%28e-x%29%7D%5Cneq%200%20%5C%5C%5C%5C%5Cto%20%28x-e%29%5E2%3D0%5C%5C%5C%5C%20%5Cto%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20x%3De%5C%5C%5C%5C%5Cto%20x%3De%2B3%5C%5C%5C%5C%5Cto%20x%3D%20e%2Ce%2B3)
So,
The critical points of 
I Think it would either be D or C
(I’m not sure, let me know if I’m wrong)
