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valkas [14]
3 years ago
14

Anika buys a pair of shin guards for $8.58 and serveral pairs of soccer socks for $4.29 per pair. If she spends 25.74 before tax

es. How many pairs of socks does anika buy
Mathematics
1 answer:
Kryger [21]3 years ago
3 0

Answer: 4 pairs of socks

Step-by-step explanation:

According to the described situation, Anika spends \$25.74 in 1 pair of shin guards for $8.58 and x pairs of socks for \$4.29 each pair.

So, we can express this in the following equation:

\$25.74=$8.58+\$4.29 x

Isolating x we will find the pairs of socks:

\$25.74-$8.58=\$4.29 x

x=\frac{\$17.16}{\$4.29}

x=4 Hence, Anika bought 4 pairs of socks.

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2. For every 3 dogs there are 4 cats.

Step-by-step explanation:

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Quadrilateral ABCD is a trapezoid with an area of 20 cm². Find the height of the trapezoid, h. Round the answer to the nearest t
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Trapezoid Area = (Bases / 2) * Height
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Sorry for the hand writing. But you want to factor out a 4y^2 which will result in (9y^2-1). Then you will factor out the equation in parentheses to (3y-1)(3y+1). Don’t forget to put the 4y^2 out front!

8 0
3 years ago
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There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

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Natalia bought 6 sweaters. 3 are blue. What fraction of the sweaters are blue?
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Answer: One-Half of the sweaters are blue.

Step-by-step explanation: Half of 6 is 3.

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