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kramer
3 years ago
7

Can someone help me I don’t get my math homework??

Mathematics
1 answer:
Doss [256]3 years ago
4 0

maybe i can  i really dont know


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Could you please explain it?
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Hello,
there are some words that I could not read. But:
I support evements are independants.
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi

Let us find first and second derivative for f(x)

f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in (0, \pi/2) U(\pi,3\pi/2)\\

and decreasing in (\pi/2, \pi)U(3\pi/2,2\pi)

x=\frac{\pi}{4}, \frac{3\pi}{4}

f"(\pi/4)

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = 2sin \pi/4+2cos \pi/4 =2\sqrt{2}

Minimum value = 2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}

c)

f"(x) =0 gives tanx =-1

x= 3\pi/4, 7\pi/4

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

3 0
3 years ago
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