3/7 ( x - 2) = 15 help plz

2 answers:

7 0

3/2 (x-2) = 15

1. Multiply 3/2 by (x-2).
3(x-2)/2 = 15 :

3x-6/7 = 15

2. Multiply 7 by both sides and canceling out the denominator on the left side.
7 (3x-6)/7 = 7(15):

3x-6 = 105

3. Subtract six from both sides.
3x-6 +6 = 105 + 6:

3x = 111

4. Divide 3 into both sides.
3x/3 = 111/3

X = 37.

Check:

1. Fill in x with your final answer.
3/7 (37-2) = 15:

3/7 (35) = 15

2. Multiply 3/7 by 35.
3/7(35) = 15:

3 (5) = 15

15 = 15

larisa [96]2 years ago

5 0

3/7 (x - 2) = 15 multiply both sides by 7/3

x - 2 = 35 add 2 to both sides

x = 37

You might be interested in

Which of the following are possible values of r?<br><img src="https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B2%20%7D%20%20%3D%20%20%5Cf

marshall27 [118]

Answer:

$r=\frac{\sqrt{3} }{4}$ and $r=-\frac{\sqrt{3} }{4}$

Step-by-step explanation:

when you solve for r in the given equation, you need to apply the square root property, which gives positive and negative answers (both should therefore be considered):

$r^2=\frac{3}{16} \\r=+/-\sqrt{\frac{3}{16}} \\r=+/-\frac{\sqrt{3} }{4}$