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Sergio039 [100]
3 years ago
15

4/10 times (7/8+9/4) 5/7​

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer: simplified down to 25/28 or 0.89 / / 0.9 rounded up

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What are the domain and range of this function y=(x+3)^2 -5
n200080 [17]

Answer: Choice A

Note: the range should be [-5, \infty). See explanation below.

===================================================

We can plug in any real number for x to get some output for y. The domain is the set of all real numbers in which we say (-\infty, \infty) which is interval notation. It represents the interval from negative infinity to positive infinity.

The range is the set of possible outputs. The smallest output possible is y = -5 which occurs at the vertex (3,-5). We can get this y value or larger. So we can describe the range as the set of y values such that y \ge -5 and that translates to the interval notation [-5, \infty).

The square bracket says "include this endpoint" while the curved parenthesis says to exclude the endpoint. Your teacher mistakenly wrote (-5, \infty) for choice A, when they should have written [-5, \infty)

I think either your teacher made a typo or somehow the formatting messed up. Either way, choice A is the closest to the answer.

8 0
3 years ago
Read 2 more answers
Determine the utilization and the efficiency for each situations:A. A loan processing operation that processes an average of 7 l
Vera_Pavlovna [14]

Answer:

A) Utilization = 70%

Efficiency = 87.5%

B) Utilization = 66.67%

Efficiency = 80%

Step-by-step explanation:

Determine the utilization and the efficiency for each situations:

A. A loan processing operation that processes an average of 7 loans per day. The operation has a design capacity of 10 loans per day and an effective capacity of 8 loans per day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = 7 loans per day

Design capacity = 10 loans per day

Utilization = 7/10 × 100

= 70%

Efficiency = Actual output / Effective capacity × 100

Actual output = 7 loans per day

Effective capacity = 8 loans per day

Efficiency = 7/8 × 100

= 87.5%

B. A furnace repair team that services and average of four furnaces a day if the design capacity is six furnaces a day and the effective capacity is five furnaces a day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = four furnaces a day

Design capacity = six furnaces a day

Utilization = 4/6 × 100

= 66.67%

Efficiency = Actual output / Effective capacity × 100

Actual output = four furnaces a day

Effective capacity = five furnaces a day

Efficiency = 4/5 × 100

= 80%

6 0
3 years ago
Three times the sum of a number 2 is the same as the number minus 4. Find the number.
Natali [406]

Answer:the number is ten

Step-by-step explanation:

5 0
4 years ago
I need help with this question
Sonbull [250]

= 4 (6) - 4 (√2) + √2 (6) - √2 <span>√2
</span>= 24 - 4√2  + 6√2 - 2 
= (24 - 2)  +  (- 4√2  + 6√2)
= 22 + √2(- 4 + 6)
= 22 + √2 (2)
= 22 + 2√2

hope it helps
5 0
3 years ago
Solve for x:
Keith_Richards [23]
It’s C because if you type it In this is what it comes out as

7 0
3 years ago
Read 2 more answers
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