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Firdavs [7]
3 years ago
5

Suppose a population has a mean weight of 180 pounds and a standard deviation of 25 pounds. a sample of 100 items is drawn from

this population. what is the standard error of the mean?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Solution: We are given:

μ=180,σ=25,n=100

Therefore the standard error of the mean is

\frac{standard deviation}{\sqrt{n}}

\frac{25}{\sqrt{100}}

2.5

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What is the measure of b?
jolli1 [7]

Answer:

16.5

Step-by-step explanation:

8 0
2 years ago
What is the greatest number of tables that can be made? Explain how did you decide on this number?
emmasim [6.3K]

The greatest number of tables that can be made is; 24 tables

<h3>Limiting Resources</h3>

To determine the limiting factor;

  • We must divide the number of all factors available by 72.

Hence, it goes that;

  • Only, 48/72= 0.66 balloons per chair
  • Only 24/72 = 0.33 flowers per chair
  • Only 32/72 = 0.44 candles per chair

However, it follows from the question that; the same number of centerpieces be used on each table.

Hence, the ratio of flowers per chair is lowest and hence, 72×0.33 flowers are used, 24 tables can therefore be set up.

Read more on limiting resources;

brainly.com/question/19231521

6 0
2 years ago
Help me please please help
Dmitrij [34]

1) 8y + 9         2) 2n + 4        3) 3d + 5h

rearrange the equations and combine like terms. combine the terms with the same variables and add / subtract them.

for example number 1:

9y - 11 + 20 - y

is the same thing as

<em>9y - y</em> <u>+ 20 - 11</u>

and now you can easily combine them:

<em>8y</em> + <u>9</u>

i hope this helps!

4 0
3 years ago
Mau bought a television for 330.The tax rate is 8% what is the total amount paid for the television
nika2105 [10]
If the tax rate is 8%, we need to find 108% of the price, or 330 times 1.08, which is $356.4
7 0
3 years ago
Solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x &lt; 360°?
Sedbober [7]

Answer:

Step-by-step explanation:

cos (x/2)=cos x+1

cos (x/2)=2cos ²(x/2)

2 cos²(x/2)-cos (x/2)=0

cos (x/2)[2 cos (x/2)-1]=0

cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)

x/2=2nπ+π/2,2nπ+3π/2

x=4nπ+π,4nπ+3π

n=0,1,2,...

x=π,3π

or x=180°,540°,...

180°∈[0,360]

so x=180°

or

2cos(x/2)-1=0

cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)

x/2=360n+60,360n+300

x=720n+120,720n+300

n=0,1,2,...

x=120,300,840,1020,...

only 120° and 300° ∈[0,360°]

Hence x=120°,180°,300°

7 0
2 years ago
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