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Mandarinka [93]
2 years ago
10

Which expression is a factor of both x2-3x+2 and

Mathematics
1 answer:
Margarita [4]2 years ago
6 0

Answer:

Step-by-step explanation:

So, factor each of the expressions and find out.  Why should anyone else factor the expressions for you?  Come on and don't be so lazy!

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90 divided by 5 in distributive property
makvit [3.9K]
Answer is 18 unless u wont it in letters
7 0
3 years ago
Read 2 more answers
Solve for x. *<br> (5x + 13)<br> (9x - 31)
ycow [4]

Answer:

x=11

Step-by-step explanation:

5x+13=9x-31

subtract 9 from both sides.

-4x+13=-31

you want to isolate the x value so subtract 13 from both sides.

-4x=-44

now divide both sides by -4.

x=11

6 0
3 years ago
Marcus is traveling from Rome to Capua on the Via Appia (a 132 mile journey). His horse and cart travels at 8 mph. How long will
nalin [4]

Answer: 16.5 hours

Step-by-step explanation:

distance=rate*time

132=8*x

Divide by 8 on both sides

x=16.5

6 0
3 years ago
Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc
nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

6 0
3 years ago
(sin (x+y)) / sinxcosy = 1+ cot(x) + tan(y)
ivann1987 [24]

Answer:

sin (×+y)/sinx cosy =1+ cotx tany

from trig ratio Sin [x +y] = sinx Cosy + cosx siny

Sinx cosy + cosox siny./Sinx cosy

then check the attachments for further information

5 0
2 years ago
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