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3 years ago

2 y - 8 / 3 equals a + 3 B / 4 solving for y

Mathematics

1 answer:

zhuklara [117]3 years ago

4 0

-2x+5
I am pretty sure

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Simon says "five time my age 4 years ago is the same as three time my age in 2 years" how old is simon

omeli [17]

Simon is 13 years old

Let x be Simon's age

Thus 4 years ago his age was (x - 4) and 2 years from now his age is (x + 2)

Hence 5(x - 4) = 3(x + 2)

distributing both sides gives

5x-20 = 3x + 6

subtract 3x from both sides of the equation

5x - 3x - 20 = 6

2x - 20 = 6

add 20 to both sides

2x = 6 + 20 = 26

divide both sides by 2

x = $\frac{26}{2}$ = 13

Simon is 13 years old

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2 years ago

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vampirchik [111]

Answer:

In khan academy, just plot the points and the answer is yes.

Step-by-step explanation:

Use the table to plot the points and you'll figure out that it's proportional- so the answer to the question below is yes. Doesn't need too much explaining.

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2 years ago

Find −5 2/3 − 1/6 Write your answer as a mixed number in simplest form.

Ksju [112]

Answer:

-5 $\frac{5}{6}$

Step-by-step explanation:

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2 years ago

All of the following devices are used in the second paragraph EXCEPT A. metaphor B. parallelism C. allusion D. abstract terms E.

Fantom [35]

What does chiasmus mean

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3 years ago

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

$hypotenuse^2=25+144$

$hypotenuse^2=169$

Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\sin \theta = \dfrac{5}{13}$

$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

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3 years ago