Answer:
Natalie bought 500 apples at $0.40 each, then she pays $0.40 500 times, this means that the total cost of the 500 apples is:
Cost = 500*$0.40 = $200
Now she threw away n apples from the 500 apples, then the number of apples that she has now is:
apples = 500 - n
And she sells the remaining apples for $0.70 each.
a) The amount that she gets by selling the apples is:
Revenue = (500 - n)*$0.70
b) We know that she did not make a loss, then the revenue must be larger than the cost, this means that:
cost ≤ revenue
$200 ≤ (500 - n)*$0.70
c) We need to solve the inequality for n.
$200 ≤ (500 - n)*$0.70
$200/$0.70 ≤ (500 - n)
285.7 ≤ 500 - n
n + 285.7 ≤ 500
n ≤ 500 - 285.7
n ≤ 214.3
Then the maximum value of n must be equal or smaller than 214.3
And n is a whole number, then we can conclude that the maximum number of rotten apples can be 214.
Given ,
7/3 = n/21
We need to find the value of n,
Cross multiplying,we get
3n = 21 x 7
=> 3n = 147
=> n = 147/3
=> n = 49 is the required answer
The equation of the demand function is D(x) = 1400√(25-x²) + 11400
<h3>How to determine the demand function?</h3>
From the question, we have the following parameters that can be used in our computation:
Marginal demand function, D'(x) = -1400x÷√25-x²
Also, we have
D = 17000, when the value of x = 3
To start with, we need to integrate the marginal demand function, D'(x)
So, we have the following representation
D(x) = 1400√(25-x²) + C
Recall that
D = 17000 at x = 3
So, we have
17000 = 1400√(25-3²) + C
Evaluate
17000 = 5600 + C
Solve for C
C = 17000 - 5600
So, we have
C = 11400
Substitute C = 11400 in D(x) = 1400√(25-x²) + C
D(x) = 1400√(25-x²) + 11400
Hence, the function is D(x) = 1400√(25-x²) + 11400
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Add up how much gets paid and how many hours he work I hope this helps good luck !!!!!!!!!!!!!!!
