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Sav [38]
3 years ago
15

How do I find X in this problem

Mathematics
2 answers:
Alona [7]3 years ago
7 0

Answer: x = 16°

Step-by-step explanation:

  • This is a right triangle, which means all angles add up to 180°.
  • One of the angle is already determined to be 90°, that means the sum of the other two angles must also be 90° in order to meet a total of 180°.

This means (x+26)° + 3x° = 90°.

Solve for x:

x + 26 + 3x = 90

x + 3x = 90 - 26

4x = 64

x = 64 ÷ 4 = 16°

Vesnalui [34]3 years ago
5 0

Answer:

x = 16

Step-by-step explanation:

First you have to know the max degrees in this figure

Since the shape is a right triangle, then the max degrees is 180°

Now that box in the triangle indicates that the angle measures 90°

180° - 90° = 90°

so for both missing angles, we're going to create a equation that satisfy to 90°

(x+26)+(3x)=90

First subtract the 26 from both sides (on 90 and on the equation)

x+3x=64   (We're left with this)

64 = 3x + x

64 = 3(16) + 16

64 = 48 + 16

64 = 64

x = 16

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Eggplant has a yield of 81%. If you purchase 12lb of eggplant, how many pounds will you be able to use?(round to the nearest hun
Aleonysh [2.5K]

Answer:

9.72 lb

Step-by-step explanation:

Yield = the amount or quantity produced or returned.

Given:

  • Yield of eggplant = 81%
  • Amount of eggplant purchased = 12 lb

To determine how many pounds of eggplant you will be able to use, calculate 81% of the amount of eggplant purchased.

\begin{aligned}\sf 81\% \: of \: 12 \: lb & = \sf \dfrac{81}{100} \cdot 12\\\\& = \sf  \dfrac{81 \cdot 12}{100}\\\\& = \sf \dfrac{972}{100}\\\\& = \sf 9.72\:lb\end{aligned}

Therefore, you will be able to use 9.72 lb (nearest hundredth).

Learn more about percentages here:

brainly.com/question/27998542

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6 0
1 year ago
Read 2 more answers
What value is equivalent to 2 × 3 + 4 − 6^2?<br> A) -26<br> B) -22<br> C) -2<br> D) 10
Yuliya22 [10]

Answer:

-26

Step-by-step explanation:

2 × 3 + 4 − 6^2

PEMDAS

exponents are first in this equation

2 × 3 + 4 − 36

Then multiply

6 +4 -36

Then add and subtract from left to right

10-36

-26

3 0
3 years ago
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A cube has side length x. One side of the cube is increased by 4 inches, and another side is doubled. The volume of the new rect
AfilCa [17]

Let

x-------> the length side  of the original cube

we have

2x^{3} +8x=450\\2x^{3}=450-8x

Divide by 2 both sides

x^{3}=225-4x

The system of equations is equal to

y=x^{3} --------> equation 1

y=225-4x --------> equation 2

using a graphing tool

see the attached figure  

we know that

the solution of the system of equations is the intersection both graphs

therefore

the solution is

x=5.86\ in

therefore

<u>the answer is</u>

5.86\ inches


6 0
3 years ago
Read 2 more answers
I need help.. i really want to go sleep.. thank you so much...
Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given  \sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}

To verify that the above equality is true or false:

Now find \sum\limits_{k=0}^8\frac{1}{k+3}

Expanding the summation we get

\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3} \sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

Now find \sum\limits_{i=3}^{11}\frac{1}{i}

Expanding the summation we get

\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

 Comparing the two series  we get,

\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i} so the given equality is true.

2) Given \sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}

Verify the above equality is true or false

Now find \sum\limits_{k=0}^4\frac{3k+3}{k+6}

Expanding the summation we get

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}

now find \sum\limits_{i=1}^3\frac{3i}{i+5}

Expanding the summation we get

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}

Comparing the series we get that the given equality is false.

ie, \sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}

6 0
3 years ago
Find the area of the shaded regions:
Crank

First, we'll find the area of the large section, including the smaller section that is white.

Area of a circle: pi x r^2

A = pi x 7^2

A = 49pi x 120/360

A = 49/3 pi cm^2

Now, we'll find the area of the small section.

A = pi x 3^2

A = 9 pi x 120/360

A = 3pi cm^2

All that's left to do now is subtract.

49/3 pi - 3 pi

40/3 pi cm^2

(or 13 1/3 = 13.33 cm^2)

Hope this helps!

6 0
3 years ago
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