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3 years ago

Which of the following equations represents a line that passes through the points

Mathematics

1 answer:

Sladkaya [172]3 years ago

5 0

Answer:

both are right

Step-by-step explanation:

okay so you already know that the y-intercept is 4 since a point is (0, 4)

but not to find the slope you can use the y2-y1/x2-x1

16 - 4/ -8 - 0 = 12/-8 = 3/-2

4 - 16/ 0 - (-8) = -12/8 = -3/2

it doesnt matter which you plug in first

so we know the slope (m) is -3/2 and the y-intercept (b) is 4, now to put it into an equation:

y = mx + b

y = -3/2x + 4

also im going to put this in slope-intercept form

3x + 2y = 8

-3x -3x

2y = -3x + 8

/2 /2

y = -3/2x + 4

y = -3/2x + 4 = y = -3/2x + 4

so both answers equal each other, meaning they both are right

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Which is greater 82\8 or 37\4.How do you know.extra answer 50 pt

ozzi

Divide both. 82/8=10.25 37/4=9.25 The first is greater.

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3 years ago

If the area of a triangular garden is 156 sq ft, and the base of this garden is 13 feet wide, what is the height?

Ilia_Sergeevich [38]

Answer:

height is =area dived by base

Step-by-step explanation:

156 divide 13 is 12

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2 years ago

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If x=7and =-2, determine the value of 6x-4y

SVEN [57.7K]

Answer:

the answer is 50

Step-by-step explanation:

first you plug in the x and y in the equation, making it 6(7)=-4(-2) then, you multiply the numbers together, making the equation 42+8. finally, you add those numbers together, giving you the answer 50

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3 years ago

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A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

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3 years ago

Complete the ratio table below to show ratios equivalent to 4:18.

liubo4ka [24]

The blanks are weird. I don't understand them!

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