Answer: We support the null hypothesis.
Step-by-step explanation:
Given : The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
The set of hypothesis for the given claim :-
A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577).
Since 12.50 contained in the 95% confidence interval (11.439 , 12.577).
Therefore, we support the null hypothesis.
So the final conclusion will be, we have evidence to support the claim that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
Answer:
中禾秝秝棕色
對他在售價將其所台
Step-by-step explanation:
女4自？日
Answer:
And for this case we can use the last equation when we want the altitude and we want to know how many minutes the plane was at air after the takeoff
Step-by-step explanation:
For this case we have the following function given :
Where:
A = feet of a plane and t = minutes after takeoff
And we are interested to solve t in terms of A
We can begin subtracting 2000 in both sides of the equation and we got:
Now we can divide both sides by 7000 and we got:
Now we can apply exponential in both sides of the equation and we got:
And now we can divide both sides by 0.2 and we got:
And for this case we can use the last equation when we want the altitude and we want to know how many minutes the plane was at air after the takeoff
First because 5x+5y=0 you can factor the 5 from equation so:
5(x+y)=5(0) => x+y=0
and by solving for x using elimination method
-8x+y=36
x+y=0
by subtracting both x and y we get
-9x=36 => x=-4
by inputing x into the "x+y=0" equation we get:
-4+y=0 => y=4
