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Irina-Kira [14]
4 years ago
6

Which expression is equivalent to on is equivalent to 9x^5y^16/45x^5y^4?

Mathematics
1 answer:
kicyunya [14]4 years ago
6 0

Answer:

\frac{y^{12} }{5}

Step-by-step explanation:

Check the attached photo for the details

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olchik [2.2K]
15:11,this is right answer
5 0
3 years ago
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Please help..<br> Solve for the area of the figure below and show work.
Serhud [2]

Answer and Step-by-step explanation:

1. We can see that this kite-shape has 4 triangles in it.

The area of a triangle is as follows:

A = \frac{bh}{2}

Where:

b = Base (length)

h = Height

<u>Top Right Triangle Area:</u>

b = 9

h = 3

A = \frac{3 * 9}{2}

A = \frac{27}{2}

<u>Bottom Right Triangle Area:</u>

b = 9

h = 3

A = \frac{3 * 9}{2}

A = \frac{27}{2}

<u>Top Left Triangle Area:</u>

b = 4

h = 3

A = \frac{4*3}{2}

A = \frac{12}{2}

A = 6

<u>Bottom Left Triangle Area:</u>

b = 4

h = 3

A = \frac{4*3}{2}

A = \frac{12}{2}

A = 6

Now, we add all the areas together to get the area of the kite figure.

A = \frac{27}{2} +

A = 27 + 12

A = 39

<u>The area of the kite figure is 39 </u>m^{2}<u>.</u>

2. We have to find the area of the trapezoid.

(I'm not sure if the 9 is for the entire bottom side length)

  • If the bottom side length is 9, then we would use the formula:

A = \frac{a + b}{2} h

to find the area of the entire trapezoid.

A = \frac{2.4 + 9}{9} × 8.2

A ≈ 46.74 mi^{2}

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

4 0
3 years ago
What is the slope of the line through (-4, 2) and (3,-3)?
vampirchik [111]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
7:5 is equivalent to 21: ?
Svet_ta [14]

Answer:

7:5 is the same as 21: 15

Step-by-step explanation:

21/7 = 3 and 3*5=15

i divided 21 by 7 to see how many times it was multiplied to get there, so i could do the same thing to the 5

I hope this helps :)

4 0
3 years ago
Read 2 more answers
Three lines intersect at point P, as shown in the diagram below. <br> Find the measure of angle VPQ.
Anna11 [10]

Answer:

angle VPQ = 83°

I hope this may be helpful

4 0
3 years ago
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